This study proposes a modified algorithm to secure medical images in cloud environments. In the proposed study, the medical image dataset will be obtained online from a standard …
We give the sufficient condition when every left-continuous (right-continuous) Hausdorff topology on a semigroup $S$ is discrete. We construct a submonoid $\mathscr{C}_{+}(a,b)$ (…
… biaj and biak, and by the rays through aj and ak perpendicular to biaj and biak respectively. Because all the A-triangles are nonobtuse, all the A-triangles attached to edges biaj or biak …
… σl,m : C+(a, b) → S0,l,m by the formula (biaj)σl,m = ((biaj)hCmg )J0,l,m, i ⩽ j, i, j ∈ ω. Since … any biaj = 1 and bkal = 1 the following equality (biaj · bkal)ς = (biaj)ς · (bkal)ς holds. Indeed, …
… has a directed edge from i to j (i = j) precisely when BiAj = 0. Let G be the subgroup of GLr(C) … i to j, and (BiAj) ∈ Mr(C) is invertible. ((BiAj) is the matrix whose entries are BiAj for different …
… Fix an arbitrary element biaj of S. Since the set E(S) is infinite… ai0 S) is infinite subset of S and biaj ∈ Ai0 . Also the above … This implies the point biaj has open finite neighbourhood in S…
… Now if x = biaj, since a interchanges x and y, we have y = bia-j and T = {biaj, bia-j, ( b i a j ) - 1 , ( b i a - j ) - 1 } . Without loss of generality we may assume that i < (p- l)/2; otherwise, we …